Calculate the resistance of two (2) resistors connected in series having the resistance of R1= 15 R2=20

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Calculate the resistance of two (2) resistors connected in series having the resistance of R1= 15 R2=20​

Answer:

Explanation:

R1 + R2 = 25 -> R1 = 25 – R2

1/R1 + 1/R2 = 1/6

1/(25-R2) + 1/R2 = 1/6

(R2 + 25 -R2) = 1/6 (25-R2) R2

150 = 25R2 – R2^2

R2^2 – 25R2 + 150 = 0

D = 625 – 4*150 = 25 = 5^2

R2 = (25 ± 5)/2 = 10; 15 (Ohm)

R1 = 15 or 10 (Ohm)

Answer: 15 Ohm and 10 Ohm.

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