Find the sum or difference , 4 5/18 – 3 13/24=, 11 17/35 – 8 29/45 + 6 11/25

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Find the sum or difference

4 5/18 – 3 13/24=

11 17/35 – 8 29/45 + 6 11/25

➜ Find the sum or difference

  • ⟩ 4 5/18 – 3 13/24
  • ⟩ 11 17/35 – 8 29/45 + 6 11/25

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\huge\tt ≼ {ANSWER} ≽

\huge 4 \frac { 5 } { 18 } - 3 \frac { 13 } { 24 }

  • ⟩ First, multiply 4 & 18 to get 72

\large\frac{72+5}{18}-\frac{3\times 24+13}{24}

\large\frac{77}{18}-\frac{3\times 24+13}{24}

\large\frac{77}{18}-\frac{72+13}{24}

\large\frac{77}{18}-\frac{85}{24}

  • ⟩ The LCM of 18 & 24 is 72. Convert the 77/18 and 85/24 to fractions with 72 as the denominator.

\large\frac{308}{72}-\frac{255}{72}

  • ⟩ The numerator can now be subtract since both have the same denominator.

\large\frac{308-255}{72}

\huge = \frac {53}{72}

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\huge 1 \frac { 17 } { 35 } - 8 \frac { 29 } { 45 } + 6 \frac { 11 } { 25 }

  • ⟩ Multiply 1 & 35 to get 35

\large\frac{35+17}{35}\large-\frac{8\times 45+29}{45}\large+\frac{6\times 25+11}{25}

\large\frac{52}{35}-\frac{8\times 45+29}{45}+\frac{6\times 25+11}{25}

\large\frac{52}{35}-\frac{360+29}{45}+\frac{6\times 25+11}{25}

\large\frac{52}{35}-\frac{389}{45}+\frac{6\times 25+11}{25}

\large\frac{468}{315}-\frac{2723}{315}+\frac{6\times 25+11}{25}

  • The LCM of 35 & 45 is 315. Convert 52/35 & 389/45 with denominator 315

\large\frac{468}{315}-\frac{2723}{315}+\frac{6\times 25+11}{25}

\large\frac{468-2723}{315}+\frac{6\times 25+11}{25}

\large\frac{-2255}{315}+\frac{6\times 25+11}{25}

  • ⟩ Reduce -255/315 to its lowest term by extracting and cancelling out 5

\large -\frac{451}{63}+\frac{6\times 25+11}{25}

\large -\frac{451}{63}+\frac{150+11}{25}

\large -\frac{451}{63}+\frac{161}{25}

\large -\frac{11275}{1575}+\frac{10143}{1575}

  • ⟩ The LCM of 63 and 25 is 1575. You can add the numerators since they both have the same denominator

\large\frac{-11275+10143}{1575}

\huge= -\frac{1132}{1575}

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\large\tt{CarryOnLearning}

\large\tt{–  Amping

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